Question

a coil in the heater consume power p on passing current . if it is out into halves and joined in parallel, it will consume power:​

Answer 1

a coil in the heater consume power p on passing current . if it is out into halves and joined in parallel, it will consume power:​ 4p.

• Given,
• a coil in the heater consumes power = p
• let r be the resistance of the coil.
• if it is out into halves and joined in parallel, then the resistance of the coil gets reduced to half = r/2
• we have a formula for the power given by,
• p = v^2/r
• power, when the coil is cut into halves and joined in parallel, is given by,
• p' = v^2 / r/2 + v^2 / r/2 = 2v^2 / r/2 = 4 v^2/r
• ∴ p' = 4 p

Answer 2

Answer:

4p

Explanation:

see atached file