Question

A coil of 100 turns and area of 2×10^-2 m^2 pivoted about a vertical diameter in a uniform magnetic field carrying a current of 5A. When the coil is held with its plane with north-south direction, it experiences a force of 0.3 Nm, when the plane is in east-west direction the torque is 0.4 Nm. What is
value of magnetic induction? And why we take MB sin theta and MB cos theta?

Answer 1

Answer:

I hope this will help you

Answer 2

Answer:

τ2=NiABsin(90−θ)=NiABcosθ ...(ii)

τ21+τ22=(NiAB)2[sin2θ+cos2θ]

NiAB=τ21+τ22−−−−−−√

100×5×2×10−2B=(0.30)2+(0.4)2−−−−−−−−−−−−√=0.5

10B=0.5⇒B=0.05T

Explanation:

give me a

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