Question

please tell answer i will give 100points and money if u ask who will answer all my questions. please fast

Answer 1

Answer:

(i)

⇒ ∠EAC = ∠EAB + ∠BAC

⇒ ∠EAC = 90° + ∠BAC    ----- (1)

⇒ ∠BAF = ∠FAC + ∠BAC

⇒ ∠BAF = 90° + ∠BAC    ---- (2)

From (1) & (2), we get

⇒ ∠EAC = ∠BAF

In ΔEAC and ΔBAF, EA = EB

⇒ In ∠EAC = ∠BAF, AC = AF

∴ ΔEAC ≅ ΔBAF

(ii)

ar(ΔEAC) = ar(ΔBAF)

⇒ ∠ABD + ∠ABC = 90° + 90°

⇒ ∠ABD + ∠ABC = 180°

(a)

ΔEAC and square ABDE are on the same base AE and between same parallel lines AF and BH.

∴ ar(ΔEAC) = (1/2) * ar(square ABDE)   ---- (3)

(b)

ΔBAF and rectangle ARHF are on the same base AF and between the same parallel lines AF and BH.

∴ ar(ΔBAF) = (1/2) * ar(rectangle ARHF)  ---- (4)

Since, ar(ΔEAC) = ar(ΔBAF)

From (3) & (4), we get

⇒ (1/2) * ar(square. ABDE) = (1/2) * ar(rectangle. ARHF)

⇒ ar(square. ABDE) = ar(rectangle. ARHF)

Hope it helps!

Step-by-step explanation:

Answer 2

Step-by-step explanation:

1)

5x - 3 > 7

5x - 3 + 3 > 7 + 3

5x > 10

5x /5 > 10/5

x = 2 answer

2)

3(x - 1) < 2( x - 3)

3x - 3 < 2x - 6

3x - 3 + 3 < 2x - 6 + 3

3x < 2x - 3

3x - 2x < 2x - 3 -2x

x < - 3 answer

3)

3x 1 + 2 x 2 < 12

just represent them in graph