Question

A coil of 100 turns is lying in a magnetic field of 1T as shown in the figure. A current of 1A is flowing in this coil. The torque acting on the coil will be​

Answer 1

Given:

A coil of 100 turns is lying in a magnetic field of 1T as shown in the figure. A current of 1A is flowing in this coil.

To find:

Torque acting on the coil.

Calculation:

Area of coil = 0.2 × 0.1 = 0.02 m².

So, let magnetic moment of coil be M ;

$\therefore \: M =n\times i \times area$

$= > \: M = 100\times1\times0.02$

$= > \: M = 2 \: amp \: {m}^{2}$

So, magnetic torque be $\tau$.

$\therefore \: \tau = B \times M \times \sin( {90}^{ \circ} )$

$= > \: \tau = B \times M \times 1$

$= > \: \tau = 1 \times( 2 )$

$= > \: \tau =2 \: N/m$

So, final answer is:

$\boxed{ \large{ \bold{ \underline{ \: \tau =2 \: N/m}}}}$