A coil of 1200 turns and mean area of 500 cmsquare is held perpendicular to a uniform magnetic field of induction 4*10power -4 . The resistance of the coil is 20 om. When the coil is rotated through 180 degree in the magnetic field in 0.1 s that average electric current (in mA) induced is?
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Answer:
24*10^-3
Explanation:
0|1=NAB
0|2=-NAB
e(avg)=2NAB/delta t
=2*1200*4*10^-4*500*10^-4/0.1
=0.48
I=E0 V/R
=0.48/20
=24*10^-3
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