Question

A coil of 150 turns is linked with a flux of 0.01 Weber when carrying a current of 10A . calculate the inductance of the coil .If the current is uniformly reversed in 0.01 sec, calculate the induced electromotive force
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Answer 1

L1 = N1Φ1/I1 = 150 × 0.01/10 = 0.15 H

e = L × di/dt = 0.15 × [10 − (−10)]/0.1 = 1 = 30 V

M = N2Φ/I1 = 100 × 0.01/10 = 0.1 H

(iii) Third Method for M As seen from

(i) M = N2Φ1/I1

∴ N2Φ1 = MI1 or - N2Φ1 = - MI1

Differentiating both sides, we get : d/dt(N2Φ1) = -M(dI1/dt) (assuming M to be constant)

Now, - d/dt(N2Φ1)  = mutually-induced e.m.f. in the second coil = eM ∴ eM = - M(dI1/dt)

If dI1/dt = 1 A/s ; eM = 1 volt, then M = 1H.

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