Question

A coil of area of cross section 0.5 m2 with 10 turns is in a plane which is perpendicular to an uniform magnetic field of 0.2 Wb m-2 . The flux through the coil is

Answer 1

flux=NBA=0.5×0.2×10=1wb

N=number of turns

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Answer 2

Given :

Area of cross section of coil , $A=0.5\ m^2$ .

Number of turns , N = 10 .

Magnetic Field , $B=0.2 \ Wb\ m^{-2}$ .

To Find :

The flux through the coil .

Solution :

We know , flux through coil is given by :

$\phi=NBA$

Putting all given values in above equation , we get .

$\phi=10\times 0.2\times 0.5\ Wb\\\\\phi=1\ Wb$

Therefore , flux through the coil is 1 Weber .

Learn More :

Magnetism

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