Question

A coil of n turns a area is placed in uniform transverse magnetic field b if it is turn through 180 about its one of the diameter in 2 seconds fing rate of change of magnetic flux through the coil

Answer 1

The value of magnetic flux through the coil is e = −10×n BA.

Explanation:

(2) emf, e = − ndφ / dt

e = − n(ϕ1−ϕ2) / t

e = − nBA (cos0° − cos 180°) / 0.2

e = − nBA (1+1) / 0.2

e = −2×n BA / 0.2

e= −10×n BA

The negative sign shows the direction of emf.

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A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is?

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Answer 2

Answer:

-NBA

Explanation:

Flux through a coil on 'N' turns is given by the formula

flux = N(B.A)

     = N(BA cos x)

(Where x is the angle between area vector and direction of field)

Here: x= 180

        hence rate of change of flux = NBA cos 180 = -NBA