Question

A
coil of radius 4 cm has 50 turns in this coil a current of 2A is flowing it is placed in a magnetic field of 0.1 weber .calculate amount of work done in rotating it through angle 180 ​

Answer 1

Answer:

work done=MB(1-cosФ)

Explanation:

hence

now M=NIA

M=50×2×3.14×16×10⁻⁴=0.5 amp-meter

as cos 180 is -1 the above formula becomes W=2MB

Hence W=2×0.5×0.1= 0.1 joule