A coil of resistance 10 ohm and an inductance of 5 henry is connected to a 100 volt battery. The energy stored in it is
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A coil of resistance 10 ohm and an inductance of 5 henry is connected to a 100 volt battery. The energy stored in it is....
solution : in case of L-R circuit,
energy stored in the inductor. i.e., E = 1/2 Li² , where L is inductance of inductor and I is current through it.
given, R = 10Ω and emf of battery, V = 100 volts
from ohm's law,
i = V/R = 100/10 = 10A
now, energy stored in it, E = 1/2 × (5H)× (10A)² = 250 J
Answered by
6
Explanation:
E=1/2Li^2, E=1/2×10×v/R=1/2×10×50/10=125joule
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