Question

A coil of resistance 300 ohm and inductance 1 henry is connected across an alternating voltage of frequency 300/2π hertz. Calculate the phase difference between the voltage and current in the circuit?

Answer 1

Given:

The resistance of the coil R= 300 ohm

Inductance L= 1 H

The frequency f= 300/2π

To find:

The phase difference between voltage and current.

Solution:

Now calculate

X(L)=2πfL

=2π×300/2π

X(L)=300

Now tanФ=X(L)/R

=300/300

=1

Ф=π/4

The difference between them is π/4