Question

A coil of wire has a resistance of
25-22 at 20°C and a resistance of
25.1762
at 35°C, What is the
temperature co-efficient of
resistance

Answer 1

Answer:

this attachment can help u

Answer 2

We will use the formula

$R_{2}=R_{1}[1+\alpha (T_{2}-T_{1})]$

$R_{1}=25.1762$     $T_{1}=20$°$C$

$R_{2}=25.22$       $T_{2}=35$°$C$

$25.22=25.1762[1+\alpha (20-35)]$

$1-15\alpha =0$

$\alpha =\frac{1}{15}$

so the temperature coefficient will be   $\frac{1}{15}$

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