Question

A coil which has a resistance of 4.2 Ω is immersed into water. If 2A current is flowing through it for 10 min then how much heat will produce in calorie?( = 4.2 J/cal)
Solution:
Given, R = 4.2 Ω, I = 2 Amp.
t = 10 minute = 10 × 60 = 600 sec
energy E = W = I2Rt
= (2)2 × 4.2 × 600 Joule
But W = JQ

Answer 1

Answer:

Resistance=4.2ohm

Current=2ampere

Time=10min or 600sec

H=I²RT

H=(2)²×4.2×600

=4×4.2×600

=10,080 joule

Also,1 Calorie=4.2 J(given)

_calories =10,080 joule

=10,080÷4.2=2400 calories