Physics, asked by rishavkeshav2777, 1 year ago

At room temperature (27°C) the resistance of thermal element is 100 Ω. If resistance of thermal element is 117 Ω, then find out the temperature of the element. Temperature coefficient of resistance of resistor is [1.70 × 10-4 C-1].
Solution:

Answers

Answered by khushboo132
0

i think the temperature will be same because resistance does not depend on temperature.

Answered by Anonymous
2

Given:-

T = 27 ° C

R = 100 Ω

Explaination:-

Let the increased temperature of the filament be T1

At T1 , the resistance of the heating element is R1 = 117 Ω

Temperature coefficient of the material used for the element is 1.70 x 10-⁴ C-¹

α = 1.70 x 10-⁴ C-¹

→ α is given by the relation

 \frac{R_{1} - R}{R(T_{1}-T)} T_{1}-T  =  \frac{R_{1} - R}{R \alpha } \\

T_{1}-27 =  \frac{117 - 100}{100(1.7x10_{-4})}  \\ T_{1}-27 = 1000

→ T1 = 1027 ° C

Therefore, the resistance of the element is 117 Ω at T 1 = 1027 ° C

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