Question

a coin is biased so that the head is twice as likely to appear as the tail. the coin is tossed twice. find the expected value of the number of heads. also find the variance of number of heads.
​

Answer 1

Answer:

Given a biased coin such that heads is 3 times as likely as tails. The coin is tossed twice.

P(H)=  

4

3

​  

 and P(T)=  

4

1

​  

 

Let T be the random variable for the number of tails.

P(T=0)=P(HH)=  

4

3

​  

×  

4

3

​  

=  

16

9

​  

 

P(T=1)=P(HT,TH)=  

4

3

​  

×  

4

1

​  

+  

4

3

​  

×  

4

1

​  

=  

16

3

​  

+  

16

3

​  

=  

8

3

​  

=  

16

6

​  

 

P(T=2)=P(TT)=  

4

1

​  

×  

4

1

​  

=  

16

1

​  

 

Step-by-step explanation:

Answer 2

1 by 2

Step-by-step explanation:

coin tosed 1 time

plz mark me as brilliant