Math, asked by parthivitiwari, 7 months ago

without actual calculations ,find the actual sum.
(i) '1 + 3+5+ 7 + 9 +11
(ii) 1+3+5 + 7 +.9 + 11 +13 + 15 + 17 + 19 + 21
(iii) 11 +13 + 15 +17 + 19 +21 + 23 + 25 + 27 +29
(iv) 13 + 15 + 17 + 19 +21 +23

Answers

Answered by piyush88147
8

Answer:

I) 36

ii) 121

iii) 200

iv) 108

Step-by-step explanation:

let me tell you that their is a trick that sum of given consecutive odd number from 1 to n terms the trick is by taking last term n is

(n+1/2)^2

so you can find it easily

hope it helps

please mark me brainliest

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