Question

A coin is drop from the top of a tower. It move through distance of 24.5m in the second before hitting the ground. Calculate the height of tower. class 9​

Answer 1

Answer:

Distances travelled in last second

S = u + a(n - 1/2)

24.5 = 0 + 9.8(n - 1/2)

n = 24.5/9.8 + 0.5

n = 3rd second

Total time of flight is 3 seconds

Height of the tower

H = 0.5gt^2

= 0.5 × 10 × 3^2

= 45 m

Height of the tower is 45 m

Answer 2

44.1m

Let the total height of the tower is h and the total time is taken to reach the ground is t.

The height is given as,

h= ½gt² (1)

The height before last seconds is given as,

h−24.5=½

g(t−1)²½gt²−24.5=½g(t)²+½g−gt

t=3s

Substitute the value of t in the equation (1), we get

h½×9.8(3)²h=44.1m

Thus, the height of the tower is 44.1m.