Physics, asked by anirudhdrg, 7 months ago

A coin is placed inside beaker, containing water to a height of 2 m. What is the apparent depth of the coin from the surface of water? (R.I. of water )

Answers

Answered by madasamy79
9

Find:

Apparently depth?

Explanation:

The coin is placed inside the beaker, so it is at a depth of 2m.

Real depth of the coin is 2m..

But, for an observer from the surface, it seems to be different(Apparently depth)

(refer image)

.Hope it is helpful

Attachments:
Answered by nairaryaashok01
0

Answer:

The apparent depth of the coin from the surface of water is 1.5m

Explanation:

Given:

Real depth=2m

Refractive Index of water=4/3

To find:
The apparent depth of the coin from the surface of water=?
Solution:

We know that,

RI=\frac{real depth}{apparent depth}

\frac{4}{3}=\frac{2}{apparent depth}

∴Apparent depth=2*3/4=1.5m

Therefore, when a coin is placed inside beaker, containing water to a height of 2m the apparent depth of the coin from the surface of water is 1.5m

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