A coin is rolling on a plane surface.what fraction of its total K.Eis rotational
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Answered by
3
Answer:
Explanation:
In case of rolling without slipping the angular velocity (ω) and the velocity of centre of mass (v) are related as: v = Rω.
Moment of inertia of the coin (disc), I = 1/2mr2
Total kinetic energy, K = Translational kinetic energy + Rotational kinetic energy
or, K = 1/2 mv2 + 1/2 Iω2
We can write rotational kinetic energy as:
1/2 Iω2 = (1/2 )×(1/2 mr2) (ω2) = 1/4 m (rω)2 = 1/4 mv2
Thus,
K total = Kt + Kr
2Kr = Kt
Ktotal = 3 Kr
Fraction of rotational kinetic energy
Kr/3 Kr = 1/3.
Hope it helps you.
Answered by
1
Answer: 1/3
Explanation:
a coin can be considers as a solid disc
moment of inertia ( I ) = MR² / 2
radius of gyration (K) = √R / √2
rotational kinetic energy = 1/2 * I * ω² [ ω = v / R ]
total energy = 1/2 mv² [ 1 + k²/r² ]
fraction = [ 1/2 * I * ω² ] ÷ [ 1/2 mv² [ 1 + k²/r² ] ] = 1/3
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