A coin is tossed 200 times a day head appears 120 times. If the coin is tossed at random the the probability of a tail is
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Answered by
3
Answer:
The probability of tail = no. of times tail appear / no. of times coin tossed
=80/200 = 2/5
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25
Answer:
Step-by-step explanation:
The key is realizing that the game only reaches the nth toss if tosses 2 to n-1 were all opposite the first toss:
HH is a palindrom
HTH is a palindrome
HTTH is a palindrome
HTTTH is a palindrome
…
Complex palindromes like HTTHTTH never occur. In this case the game would have ended at the 4th toss.
So the probability that the game continues to the nth toss is P(n) = (1/2)^(n-2). As n approaches infinity, P(n) approaches zero.
(Vihren Lindrov said it in a different way, but definitely said it before I did.)
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