Question

A coin is tossed 3 times find the probability of getting at most 1 gead​

Answer 1

Answer:

ur ans is 1/2 .......................

Answer 2

Answer:

s={THT,TTT,HTH,HHH,THH,HTT,HHT,TTH}

n(s)={8}

A={THT,HTH,HHH,THH,HTT,HHT,TTH}

n(A)={7}

P(A)=n(A)/n(S)

=7/8

probability of getting at least one head is 7/8

hope it helps u.