a coin is tossed 3 times find the probability of not getting the same result in all the tossess
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the coin is tossed 3 times
S={HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
n(S)=8
let A be an event of not getting the same result in all the tosses
A={HHT,HTH,HTT,THH,THT,TTH}
n(A)=6
P(A)=n(A)/n(S)
=6/8
=3/4
=0.75
S={HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
n(S)=8
let A be an event of not getting the same result in all the tosses
A={HHT,HTH,HTT,THH,THT,TTH}
n(A)=6
P(A)=n(A)/n(S)
=6/8
=3/4
=0.75
Answered by
4
The probability of not getting the same result in all the tosses is
Step-by-step explanation:
Given : A coin is tossed 3 times.
To find : The probability of not getting the same result in all the tosses ?
Solution :
When the coin is tossed 3 times,
S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} = 8
The favorable outcome of not getting the same result in all the tosses
i.e. {HHT, HTH, HTT, THH, THT, TTH}=6
The probability of not getting the same result in all the tosses is given by,
#Learn more
If two dice are thrown simultaneously, then the probability of getting a doublet or a total of 6 is
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