Question

A coin Is tossed 80 times and the head is obtained 38 times now if a coin is tossed once what will be the probability of getting:

• A Tail
Answer is :-
$\frac{21}{40}$
• A Head
Answer is :-
$\frac{19}{40}$
✿NOTE :- Answer I have Already mentioned So, just explain me how it came.

✿Need full explanation
✿Thank You

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Answer 1

$\large{\underbrace{\underline{\bf{Question:-}}}}$

A coin is tossed 80 times and the head is obtained 38 times. Now, if a coin is tossed once, what will be the probability of getting :

• A Tail
• A Head

$\large{\underbrace{\underline{\bf{Required\:Answer:-}}}}$

$\underline{\underline{\frak{\green\dag\;Before\:Solving:}}}$

• Probability : It means possibility of occurence of any particular event . It may range from 0 to 1 .

• It is unit-less quantity.

• In this question, we would simply find the number of favorable outcomes and then divide it by the total number of outcomes so as to get the answer.

• We know that, when a coin is tossed, we can get only two results that are Heads or Tails .

$\underline{\underline{\frak{\green\dag\;Solution:}}}$

» It is given that, the coin is tossed 80 times so,

$\dashrightarrow$ Total Outcomes = 80

» The total outcomes would remain the same for both the cases.

» The formula for finding the probability of any event is :

$\quad\quad\quad\boxed{\sf{P_{\:(event) }=\dfrac{Favorable\:Outcomes}{Total\:Outcomes}}}$

★ Probability of getting Heads :

• Favorable Outcomes = 38

$\quad\quad\quad \colon \rightarrow \sf \: Probability _{ \: (Heads)} = \cancel \dfrac{38}{80}$

$\quad \quad \quad \colon \rightarrow \underline{ \boxed{ \rm{ \pink{Probability _{ \: (Heads)} = \red{ \bf\frac{19}{40}}}}} }$

★ Probability of getting Tails :

• Favorable Outcomes = 80 - 38 = 42

$\quad\quad\quad \colon \rightarrow \sf \: Probability _{ \: (Tails)} = \cancel \dfrac{42}{80}$

$\quad \quad \quad \colon \rightarrow \underline{ \boxed{ \rm{ \red{Probability _{ \: (Tails)} = \pink{ \bf\frac{21}{40}}}}} }$

_____________________________

Answer 2

Answer:

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