A coin is tossed and a die is thrown simultaneously. A is an event of getting a head and an even number then find n(A).
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Answer:
option c
Step-by-step explanation:
A coin is tossed and a die is thrown simultaneously.
S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}
Thus n(S)=12
P is the event of getting head and an odd number.
P={H1,H3,H5}
Thus n(P)=3
Q is the event of getting either H or T and an even number.
Q={H2,H4,H6,T2,T4,T6}
Thus n(Q)=6
R is the event of getting a number greater than 7 and tail 1.
R={}
∴n(R)=0
Hence, option C is correct.
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