Math, asked by shaikhshemina2504, 6 months ago

A coin is tossed and a die is thrown simultaneously. A is an event of getting a head and an even number then find n(A).​

Answers

Answered by karajini2004
2

Answer:

option c

Step-by-step explanation:

A coin is tossed and a die is thrown simultaneously.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

Thus n(S)=12

P is the event of getting head and an odd number.

P={H1,H3,H5}

Thus n(P)=3

Q is the event of getting either H or T and an even number.

Q={H2,H4,H6,T2,T4,T6}

Thus n(Q)=6

R is the event of getting a number greater than 7 and tail 1.

R={}

∴n(R)=0

Hence, option C is correct.

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