A coin is tossed (m + n) times (m > n). The probability of getting at least m consecutive heads is
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Answer :(N+2/2^M+1)
Step-by-step explanation:
Let M be an an event of getting at least consecutive head.
∴Probability (getting at least M consecutive heads) =
Probability(getting consecutive heads in first M tosses) +
Probability(getting tail in the first toss, getting at least M consecutive heads second toss onwards) +
Probability(getting tail in the second toss, getting at least M consecutive heads third toss onwards) +
.
.
.
Probability(getting tail in the Nth toss, getting M consecutive heads in last M tosses)
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