Question

A compound x contains 82.76 of carbon by mass and 17.24 of hydrogen by mass

Answer 1

Answer:

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Answer 2

The empirical formula of the compound is $C_2H_5$

Explanation:

We are given:

Mass of Carbon = 82.76 g

Mass of Hydrogen = 17.24 g

To formulate the empirical formula, we need to follow some steps:

• Step 1: Converting the given masses into moles.

Moles of Carbon =$\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{82.76g}{12g/mole}=6.89moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{17.24g}{1g/mole}=17.24moles$

• Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 6.89 moles.

For Carbon = $\frac{6.89}{6.89}=1$

For Hydrogen = $\frac{17.24}{6.89}=2.5$

To make the mole ratio, a whole number, we multiply the mole ratios of each element by '2'

Mole ratio of carbon = (2 × 1) = 2

Mole ratio of hydrogen = (2 × 2.5) =5

• Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 2 : 5

The empirical formula of the compound is $C_2H_5$

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