Question

a coin is tossed three time find the probability of
(i) getting atleast two heads
(ii) getting exactly one tail​

Answer 1

Step-by-step explanation:

Sample space: { HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}

Total number of possible outcomes=8

(i) A getting at least two heads

P(A)=P(getting two heads)+P(getting 3 heads)

= 3/8+ 1/8

(using formula=P(event)=

No of favorable outcomes. ÷ Total no of possible outcomes

P(a)=4/8

P(a)=1/2

ii) exactly one tail

Total number of possible outcomes=8

(using formula=P(event)=>

No of favorable outcomes. ÷ Total no of possible outcomes

P(a)3÷8

P(a)=>3/8

plz mark brainliest this answer

Answer 2

Answer:

ncu. lxhncub fi. ivx d inch so jaan

Step-by-step explanation:

xgjzzt vdimctbcsgv to be dekha hai