a coin is tossed three times .find the probability of getting one tail and two tails
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total outcomes = 8
one tail and two tail=== ( THH) ( HTH) (HHT)(TTH) ( HTT)(THT)
P(E) = No. of favourable outcomes / total
P(E) = 6/8
P(E) = 3/4
one tail and two tail=== ( THH) ( HTH) (HHT)(TTH) ( HTT)(THT)
P(E) = No. of favourable outcomes / total
P(E) = 6/8
P(E) = 3/4
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