A coin is tossed thrice
1)find probability of getting at most three tails.
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1
S={H H H
H H T
H T H
H T T
T H H
T H T
T T H
T T T}
n(S)=8
SO A{TTT,TTH,THT,HTT,HHT,HTH,THH}
n(A)=7
P(A)=n(A)/n(S)
=7/8
H H T
H T H
H T T
T H H
T H T
T T H
T T T}
n(S)=8
SO A{TTT,TTH,THT,HTT,HHT,HTH,THH}
n(A)=7
P(A)=n(A)/n(S)
=7/8
Aami11:
brainliest plz
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bt first check the ans if u want
yeah ri8
Answered by
2
All possible events=hhh,ttt,hht,thh,hth,tht,tth,htt
No. Of possible events=8
Favourable events=ttt,hht,thh,hth,tht,tth,htt
No. Of favourable events=7
P(E)=7/8
No. Of possible events=8
Favourable events=ttt,hht,thh,hth,tht,tth,htt
No. Of favourable events=7
P(E)=7/8
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