A coin is tossed thrice what is the probability that at least one tail locker
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n(s) =8
n(A) =1
P(A) =n(A) /n(s) =1/8
n(A) =1
P(A) =n(A) /n(s) =1/8
Answered by
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Answer:
at least tail
it means there is total 8 options
inthat 7 are having tails atleast
so
n(E)=7
n(S)=8
p=7/8
Step-by-step explanation:
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