Question

a coin kept inside water of refractive index 4 by 3 when viewed from air in a vertical direction appears to be raised by 0.3 millimetre find the depth of coin in water​

Answer 1

Answer:

Given, meu = 4/3,

shift = 0.3mm.

Let real depth be x mm.

Therefore,

Apparent depth = x/meu

= x/(4/3)

= 3x/4

Shift = real depth - apparent depth.

= x - 3x/4 = x/4

Given,

Shift = x/4 = 0.3mm

Therefore,

x = 1.2mm

Thus, depth of coin in water = 1.2mm.