Question

a coin purse contains two 25-centavo coins,three 1-peso coin,four 5-peso coins,and five 10-peso coins.what is the probability of getting either a 1 peso coins or a 10-peso coin?

Answer 1

Answer:

probability Will be 4/7

Answer 2

Answer:

probability of getting either a 1 peso coins or a 10-peso coin is 0.57

Step-by-step explanation:

given, there are  two 25-centavo coins,three 1-peso coin,four 5-peso coins,and five 10-peso coins

to find: probability of getting either a 1 peso coins or a 10-peso coin

$probability \ of \ an \ event=\frac{number \ of \ favorable \ outcomes}{total \ number \ of \ outcomes}$

total 14 coins

probability of getting 1 peso coin P[A] = $\frac{3}{14}$

probability of getting 10 peso coin P[B] = $\frac{5}{14}$

here, A and B are disjoint sets, they do not have any elements in common

$P(AUB) = P(A)+P(B)$

probability of getting either a 1 peso coins or a 10-peso coin = probability of getting 1 peso coin + probability of getting 10 peso coin

           = $\frac{3+5}{14}$

           = $\frac{8}{14}$ = 0.57

Thus, probability of getting either a 1 peso coins or a 10-peso coin is 0.57