Math, asked by indrani9karmakar, 4 months ago

A collage is made up of 400 rhombus shaped pieces and 200 trapezium shaped pieces. The diagonals of the rhombus are 6cm and 4 cm long. The lengths of the parallel sides of the trapezium are 4cm and 8cm , and height is 10cm. Find the area of the collage and also the cost of painting it at the rate of Rs. 250 per sq. m.

Answers

Answered by tennetiraj86
11

Answer:

Area of the collage = 16800 sq.cm or 1.68 sq.m

Total cost of painting the collage =Rs.420

Step-by-step explanation:

Given:-

A collage is made up of 400 rhombus shaped pieces and 200 trapezium shaped pieces. The diagonals of the rhombus are 6cm and 4 cm long. The lengths of the parallel sides of the trapezium are 4cm and 8cm , and height is 10cm.

To find:-

Find the area of the collage and also the cost of painting it at the rate of Rs. 250 per sq. m.

Solution:-

Given collage is made up of rhombus shaped pieces and Trapezium shaped pieces.

Diagonals of rhombus=6cm and 4cm

Let d1=6cm

d2=4cm

Area of Rhombus=(d1×d2)/2sq.units

Area of rhombus=(6×4)/2 sq.cm

Area of rhombus=6×2 sq.cm

Area of rhombus=12 sq.cm

Total number of rhombus pieces=400

Total area of all rhombus pieces

=400×12=4800 sq.cm--------------------(1)

The lengths of the parallel sides of the trapezium are 4cm and 8cm

Let a=4cm

b=8cm

height =(h)=10cm.

Area of Trapezium=h(a+b)/2 sq.units

Area of Trapezium=10(4+8)/2 sq.cm

Area of Trapezium=10(12)/2 sq.cm

Area of Trapezium=10×6 sq.cm

Area of Trapezium=60 sq.cm

Number of all Trapezium pieces=200

Total area of all Trapezium pieces

=200×60

=12000 sq.cm---------------------------(2)

Total area of the collage=Area of all rhombus pieces+Area of all Trapezium pieces

=>Total area of collage=4800+12000

=>Total area of the collage =16800 sq.cm

we know that 10000 sq.cm=1 sq.m

16800 sq.cm=16800/10000=1.68 sq.m

The cost of painting the collage per 1 sq.m

=Rs.250

The cost of Painting the collage of 1.68 sq.m

=1.68×Rs.250

=Rs.420

Using Concept:-

Total area of the collage=Area of all rhombus pieces+Area of all Trapezium pieces.

Using formulae:-

  • Area of Rhombus=d1×d2/2 sq.units
  • Here, d1 and d2 are the diagonals of the rhombus.
  • Area of Trapezium=h(a+b)/2 sq.units
  • Here, a and b are the parallel sides and h is the height of the Trapezium.

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