Question

A college awarded 38 medals in volley ball, 15 in foot ball and 20 in basketball. The medals awarded to a total of 58 player and only three players got medal in all three sport how many receive medal in axactly two of the three players

Answer 1

Step-by-step explanation:

Let the required value be x.

According to rule of sets,

number of players awarded= number of players awarded for volley ball + number of players awarded for football + number of players awarded for basketball -(number players awarded for volleyball and football + number of players awarded for basketball and football+ number of players awarded for basketball and volleyball) + number players awarded for basketball, football and volleyball

58=38+15+20-(x)+3

58=73+3-x

58=76-x

x =76-58=18

Answer 2

Let,

V = set of students getting medals in volleyball

F = set of students getting medals in football

B = set of students getting medals in basket ball

We are given the following:

n ( V ) = 38,

n ( F ) = 15

n ( B ) = 20

n ( V U F U B ) = 58

n ( V ∩ F ∩ B ) = 3

Let,

a = Number of students getting medals in volleyball and football but not the basketball

b = Number of students getting medals in football and basketball but not volleyball

c = Number of students getting medals in basketball and volleyball but not football

So,

n ( V U F U B ) is as follows :

⇒ [ 38 - ( a + c + 3 ) ] + [ 15 - ( a + b + 3 ) ] + [ 20 - ( b + c + 3 ) ] + a + b + c = 58

⇒ 67 - ( a + b + c ) = 58

⇒ a + b + c = 9

∴ Number of players who received medals in exactly two of the three sports,

⇒ a + b + c

⇒ 9

∴ Number of players who received medals in exactly two of the three sports is 9 respectively.