Chemistry, asked by Nishant9917, 9 months ago

A colloidal solution is subjected to an electric field. The
particles move towards anode. The coagulation of same sol
is studied using NaCl, BaCl₂ and AlCl3 solutions. The order
of their coagulation power should be –
(a) NaCl > BaCl₂ > AlCl₃ (b) BaCl₂ > AlCl₃ > NaCl
(c) AlCl₃ > BaCl₂ > NaCl (d) BaCl₂ > NaCl > AlCl₃

Answers

Answered by maqbeth2255
0

Answer:

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Answered by Anonymous
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The order of the coagulation power is AlCl₃ > BaCl₂ > NaCl.

  • According to the law of Hardy Schulze, the effective electrolyte ions which cause the coagulation are those carrying a charge which is contrary to that of the colloidal particles.
  • The greater there is valence of the coagulating or the fluctuating ion, the greater will be its overall coagulation-causing strength.
  • If the colloidal solution gets exposed to an electrical field, the coagulating force should be in the sequence of AlCl₃ > BaCl₂ > NaCl  as the valence rises.
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