Question

A colour blind man marries a woman, who is homozygous for normal colour vision, the

probability of their son been colour blind is …..

a. 25% b. 50%

c. 0% d. 100%​

Answer 1

Answer:

a 50% I suppose.

Explanation:

50% chance.

Answer 2

Explanation:

chromosome for male is xy in which date get the X chromosome from their mother and if this X chromosome contains the gene for colour blindness they are known to be colour blind where is the chromosome for female is x x in which one x chromosome they get from the mother and another X chromosome they get from the father so if one of the X chromosome in a female is having the gene that causes colour blind then she is known as the carrier and if both the X chromosome of the female is affected then she is colorblind

now if we draw a punnett square on which one site contains affected X chromosome and Y chromosome and another side contains normal X chromosomes

as you can see in the above diagram in the punnett square x y doesn't have the affected Jin so the answer is 0% that is the chance of a male child getting the disease is Nil but the girl child will be the carrier of the disease as one of the X chromosome is affected