Question

A column of water 0.60 supports a 0.32 column of a unknown liquid .What is the density of the liquid ?

Answer 1

Solution:-

As the pressure exerted by both the column at the base of water column is equal to the atmospheric water.

considered p be the density of the liquid.

hpg + h'pwg = 1atm = 1.01325 * 10^5

h = 0.32m and h' = 0.60 m

Pw = 10³ kg/m³. (Answer).

________##Thanks.

Answer 2

Explanation:

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|||||| ans.= 1875 kg/m³. ||||

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