A force of 15 N acts for 5 s on a body of mass 5 Kg which is initially at rest. Calculate.a) Final velocity of the body.
b) The displacement of the body.
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a) As we know,
F=ma
15N=5×a
a=3m/s²
Now,
a=(v-u)/t
3=(v-0)/10 (u=0m/s as the object initially at rest)
v=30m/s
b)From equation of motion:v²-u²=2as
30²-0²=2×3×s
s=150 m
Hope it will help you.
F=ma
15N=5×a
a=3m/s²
Now,
a=(v-u)/t
3=(v-0)/10 (u=0m/s as the object initially at rest)
v=30m/s
b)From equation of motion:v²-u²=2as
30²-0²=2×3×s
s=150 m
Hope it will help you.
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