a comet having a mass of 8.36 ×10^ 11 kg strikes the earth at a relative speed of 30 km per second. Compute the kinetic energy of the comet in megatons of TNT.
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Answer:
Here, r=R+h=6.4×10
6
+3.6×10
6
=10
7
m.
Orbital velocity of the satellite around the earth is given by
v
0
=
(R+h)
GM
=
10
7
6.67×10
−11
×6×10
24
=
6.67×6×10
6
ms
−1
a. KE of the satellite =1/2mv
e
2
=
2
1
×500×6.67×6×10
6
=10
10
J
b. PE of the satellite=−
R+h
GMm
=−
10
7
6.67×10
−11
×(6×10
24
)×500
=−2×10
10
J
c. Total energy =KE+PE=10
10
−2×10
10
=−10
10
J
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