Question

A comical tent with height is 6m and slant height is 10m has to be made at the cost 150per m2 what will be the total cost​

Answer 1

Given:

• Height of conical tent = 6 m

• Slant height of conical tent = 10 m

• Cost = 150 per m²

To find out :

Find the total cost of conical tent?

Formula used:

Area of conical tent = πrl

Solution:

We have ,slant height = 10 m and height = 6 m

Let r cm be theslant height radiusof the cone. Then ,

l² = r² + h²

⇒ 10² = r² + 6²

⇒ 100 = r² + 36

⇒ r² = 100 - 36

⇒ r² = 64

⇒ r = 8 m

Area of conical tent = πrl

☆ Putting the values in the above formula ,we get

Surface area = 22/7 ⨯ 8 ⨯ 10

= 1760/7

= 251.42 m² ( approx )

Now,

Cost of conical tent = 251.42 ⨯ 150

= Rs 37713

Answer 2

✯✯ QUESTION ✯✯

A conical tent with height is 6m and slant height is 10m has to be made at the cost 150per m2 what will be the total cost..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Height=6m}$

$\longmapsto\tt{Slant\:Height=10m}$

$\longmapsto\tt{Area\:of\:Conical\:Tent=\pi{rl}}$

As Radius of Conic Tent is not given.So,Firstly we will find the Radius..For this : -

➙ l² = h² + r²

➙10² = r² + 6²

➙100 = r² + 36

➙100 - 36 = r²

➙64 = r²

➙√64 = r²

➙Radius = 8m.

☛Now ,

$\longmapsto\tt{\small{\boxed{\bold{\bold{\green{\sf{C.S.A\:of\:Cone=\pi{rl}}}}}}}}$

☛Putting Values : -

$\longmapsto\tt{\dfrac{22}{7}\times{8}\times{10}}$

$\longmapsto\tt{\cancel\dfrac{1760}{7}}$

$\longmapsto\tt{\small{\boxed{\bold{\bold{\orange{\sf{251.42{m}^{2}(Approx.)}}}}}}}$

$\longmapsto\tt{Cost\:of\:Conical\:Tent = 251.42\times{150}}$

$\longmapsto\tt{\large{\boxed{\bold{\bold{\purple{\sf{37713{m}^{2}}}}}}}}$

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➥Some More Formulas: -

• T.S.A of Cone = πr (l + r)
• Volume of Cone = 1/3 πr²h