A commitee of 3 members is to be made out of 6 men and 5 women what is the probability that the commitee has at least two women?
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Answered by
1
Step-by-step explanation:
Total cases = 4C1. 6C4 + 4C2. 6C3 + 4C3. 6C2+ 4C4. 6C1 +6C5
= 60+ 120+60+6+6
= 252
Favourable cases (at least one women present in the committee)
= 4C1. 6C4 + 4C2. 6C3 + 4C3. 6C2+ 4C4. 6C1
= 60+120+60+6
=246
Therefore, the required probability = 246/252
=41/42
the correct probability is 14/33..
Hope its help.
Answered by
0
Step-by-step explanation:
the correct probability is 14/33.
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