Question

A committee consists of 9 experts taken from three institutions a, b and c, of which 2 are from a, 3 from b and
4 from
c. If three experts resign, then the probability that they belong to different institutions is

Answer 1

Answer:

Probability that they belong to different institutions =

1-probability thatbelong to same institution

no of ways so that they belong to same institutions =5

total no of ways = 84

probability thatbelong to same institution = 5/84

probability that they belong to different institutions =

1- 5/84 = 79/84

attaching solution

(answer would have been different if all three are from different institution in that question no of ways would have been 24 & answer : 24/84 = 2/7)
I Hope it will help!

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