Question

a mixture comprises water and liquids a and b. The volume of water is 1/3 of the total mixture and the volume of liquids a and b are in the ratio 5:3. To remove the water, the mixture is passed through a porous medium which completely absorbs the water and partially absorbs liquid a. Altogether this porous medium absorb

Answer 1

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The question is incomplete. But don't worry I've know this question from my previous studies.

● Answer- 120 ml

● Explanation-
We have a/b = 5/3
Suppose, a = 5x, b = 3x,
Also Water / a+b = (1/3)/(1-1/3)
Water = (5x+3x)×1/2 = 4x

Total mixture initially,
V1 = 5x+3x+4x = 12x

Later,
b = 3x
a/b = 7/9
a = 7/9 × 3x
a = 7/3 x

Total mixture finally,
V2 = 7x/3 + 3x
V2 = 16x/3 ...(1)

But its given,
V2 = V1-200
V2 = 12x-200 ...(2)

Equating (1) & (2),
16x/3 = 12x-200
20x/3 = 200
x = 30 ml

Water absorbed = 4x = 120 ml

Hope this is helpful...