A slab consists of two parallel layers of two different materials of same thickness having thermal conductivities k1 and k2 .the equivalent thermal conductivityof the slab is ________
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Answered by
39
Hey dear,
● Answer-
k = (k1+k2)/2
● Explaination-
Let two slabs of same thickness t and area of cross section A be joined.
Resultant conductance is given by-
k = (k1A + k2A) / (A + A)
k = (k1 + k2) / 2
Thermal conductivity of the combination is (k1+k2)/2 .
Hope this helps you.
Thanks for asking.
● Answer-
k = (k1+k2)/2
● Explaination-
Let two slabs of same thickness t and area of cross section A be joined.
Resultant conductance is given by-
k = (k1A + k2A) / (A + A)
k = (k1 + k2) / 2
Thermal conductivity of the combination is (k1+k2)/2 .
Hope this helps you.
Thanks for asking.
Answered by
21
Explanation:
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