a committee of 3 experts is to be selected out of a panel of 7 persons.,three of them are lawyer, three of them are c.a and 1 is both a c.a and a lawyer.in how many ways the committee be selected if it must have atleast a c.a and a lawyer
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» 70,000 + 5,90,000 - 60,000
⇒ 6,00,000
C = 6,00,000
Gross t = Net S - Cost
⇒ Gross = 7,20,000 - 6,00,000
⇒ 1,20,000
Gross =1,20,000
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