Question

If the error in measuring the momentum of an object is 50%, what is the error in measuring the kinetic energy?​

Answer 1

Answer:

50 ×2

= 100

Explanation:

error counts as the in front constant is equal to the power iof the quantity..

so

k= (2mp)^1/2

Answer 2

Answer:

dE/E=2(dP/P) (here E=kinetic energy ,P =momentum)

or,The error in measuring the kinetic energy =(2x50)%=100%

Explanation:

We know that E=p²/2m

so,log E=2log P (2m =constant)

so,dE/E=2(dP/P) (d carries the sigh delta)