Math, asked by connor74, 1 year ago

A committee of 3 ladies and 4 gents is to be formed out of 8 ladies and 7 Gents mrs X refuses to serve in a committee in which Mr y is member. the number of such commitees is

Answers

Answered by ashisingh65289
138

Let us first form a committee with 3 ladies  and 4 gents.

>>7C4*8C3 =7C4= 7*6*5 / 3*2*1 = 35

8C3 = 8*7*6/3*2*1 = 56

We get 56*35 = 1960

  Let us calculate the possibility when  

Mrs.X and Mr. Y are together.  

>>6c3*7c2 =  6c3 = 6*5*4/3*2*1 = 20

7c2= 7*6/2*1 = 21

We get 20 * 21 = 420

thus, 1960-420 = 1540

      


connor74: helpful
ashisingh65289: thnxx
Answered by amitnrw
20

Given  : committee of 3 ladies and 4 gents is to be formed out of 8 ladies and 7 Gents So That Mrs .X And Mr.Y do not Come together

To Find : Total Number of Committees which can be formed

Solution:

Total = 7 Men  and 8 Women

Committee to be formed

4 Men and 3 Women

3 Women out of 8 Women can be selected in ⁸C₃  = 56  ways

4  Men  out of 7  Men can be selected  in ⁷C₄  =  35 ways

Total = 56 x 35 = 1960

Mrs.X And Mr.Y can not be together

Cases when X & Y are Selected

Then remaining 2 Women out of 7 Women can be selected in  in ⁷C₂ = 21 Ways

Then remaining 3  Men  out of 6  men can be selected  in in ⁶C₃ = 20 Ways

 X & Y are together  = 21 x 20 = 420

When X & Y are not together  then 1960 - 420 = 1540 Ways

Total Ways committee can be formed =  1540 ways

in 1540 ways committees can be formed of 4 Men And 3 Women From 7 Men And 8 Women So That Mrs.X And Mr.Y Do Not Come together

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