Math, asked by ababb786, 6 months ago

A committee of 8 is to be selected out of 6 males and 8 fomales. In how many ways can it be formed so that the males may not be out-numbered ?​

Answers

Answered by brainlyboy1248
12

A committee of 8 is to be selected out of 6 males and 8 females. In how many ways can it beformed so that the male way not be out numbered?

6males/2females: 6C6*8C2 = 1*28 = 28 ways

5males/3females: 6C5*8C3 = 6*56 = 336 ways

4males/4females: 6C4*8C4 = 15*70 = 1050 ways

Total # of ways: 28+336+1050 = 1414

Similar questions