A committee of two person is selected from 2 men and 2 women what is the probability that the committee will have no made a no man? (a)no men
committee of two womens
(b) one man in a committee means that there is one
women one man out of
(c) two can be selected 2c2 ways?
Answers
Answer:
Hope it will help you
To understand this question you should also have knowledge of combinations and permutation.
let's do the question . . .
SOLUTION: If no man is selected, it means only women are selected
So, we have to select 2 women
Total number of persons = 2 + 2 = 4
Number of persons to be selected = 2
Number of ways both women is selected = 2
P(no man is selected) = Number of ways both women is selected/total number of ways ...(1)
Total Number of ways = 4C2
=4! /2!(4-2)!
=4!/2!(2)!
=4 x 3 X 2! /2x1x2!
= 6
Number of women = 2
Number of women to be selected = 2
Number of ways both women is selected = 2C2
=2!/(2-2)!
= 2! /2!0!
=2!/2! x1
= 1 ways
Putting values in (1)
P(no man is selected) = Number of ways both women is selected /Total number of ways
=1/6
this is 1st part mark me as brainliest to get 2nd &3rd part