Physics, asked by anupallavi7088, 11 months ago

A common emitter amplifier has a voltage gain of 50, an input impedance of 100 ohm and an output impedance 200 ohm . The power gain of the amplifier is

Answers

Answered by Anonymous
66

Hey mate!!

________________________________________________________________

Impedance gain= output impedance / input impedance

→ Voltage gain = beeta × impedeance gain

→50 = beeta × 200/100

→ beeta = 25

Now,

Power gain = (beeta)² × impedeance gain

Power gain = 25 × 25 × 2

Power gain = 1250

Hope it helps!!

#Jaihind


Anonymous: hey
Answered by lidaralbany
9

Answer:

The power gain of the amplifiers is 1250.

Explanation:

Given that,

Voltage gain = 50

Input impedance = 100  ohm

Output impedance = 200 ohm

A_{Z}=\dfrac{Z_{o}}{Z_{in}}

Here,

A_{Z}= Impedance\ gain

A_{Z}=\dfrac{200}{100}

A_{Z}=2

We know the formula of voltage gain

A_{v}=\beta\times A_{Z}

50=\beta\times2

\beta=25

Now, The power gain is

A_{p}=\beta^2\timesA_{Z}

A_{p}=25\times25\times2

A_{p}=1250

Hence, The power gain of the amplifiers is 1250.

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